I am noticing that this is returning the original size of the image when it was opened, and not the size it may have been resized to with scaleImage or resizeImage.(PECL imagick 2, PECL imagick 3)
Imagick::getImageWidth β ΠΠΎΠ·Π²ΡΠ°ΡΠ°Π΅Ρ ΡΠΈΡΠΈΠ½Ρ ΠΈΠ·ΠΎΠ±ΡΠ°ΠΆΠ΅Π½ΠΈΡ
ΠΠΎΠ·Π²ΡΠ°ΡΠ°Π΅Ρ ΡΠΈΡΠΈΠ½Ρ ΠΈΠ·ΠΎΠ±ΡΠ°ΠΆΠ΅Π½ΠΈΡ.
Π‘ΠΈΠ³Π½Π°ΡΡΡΠ° ΡΡΠ½ΠΊΡΠΈΠΈ Π½Π΅ ΡΠΎΠ΄Π΅ΡΠΆΠΈΡ ΠΏΠ°ΡΠ°ΠΌΠ΅ΡΡΠΎΠ².
ΠΠΎΠ·Π²ΡΠ°ΡΠ°Π΅Ρ ΡΠΈΡΠΈΠ½Ρ ΠΈΠ·ΠΎΠ±ΡΠ°ΠΆΠ΅Π½ΠΈΡ Π² ΠΏΠΈΠΊΡΠ΅Π»ΡΡ .
Π€ΡΠ½ΠΊΡΠΈΡ Π²ΡΠ±ΡΠ°ΡΡΠ²Π°Π΅Ρ ΠΈΡΠΊΠ»ΡΡΠ΅Π½ΠΈΠ΅ ImagickException, Π΅ΡΠ»ΠΈ Π²ΠΎΠ·Π½ΠΈΠΊΠ»Π° ΠΎΡΠΈΠ±ΠΊΠ°.
I am noticing that this is returning the original size of the image when it was opened, and not the size it may have been resized to with scaleImage or resizeImage.<?php
$image = new Imagick("picture.jpg");
$width = $image->getImageWidth();
print "the image width is " . $width . " pixels";
?>
Will print:
the image width is 200 pixels"bob at majdak dot net" mentioned that this function does not return the resized image size.
I use this function in production code, and it correctly returns the width for an image resized with `resizeImage()`.
I have not tested it with `scaleImage()`.